UVa OJ Board

Print blank line between two cases. like this Input: 330000 330000 Output: This is leap year. This is huluculu festival year. This is bulukulu festival year. This is leap year. This is huluculu festival year. This is bulukulu festival year. But your output: This is leap year. This is huluculu festiv...

Try the input Input: 3 10 .......... .......... .......... .......... .......... .......... .......... .......... .......... ....W..... 20 .................... .................... .................... .................... .................... .................... .................... .................

For check Overflow You can use int bit = 64; int power= ceil(bit / (log(powerBase)/log(2))); Example: 1. If powerBase=3 then power=41 (i.e. the maximum power of 3 is 40, 3^40 < 2^64-1(unsigned long long range)). 3^41 is overflow at 64 bit integer. 2. If powerBase=5 then power=28 (i.e. the maximum po...

Try this Input: 100000001010001010001010001000101000101000101000010000000101000101000101000100010100010100010100001 100000001010001010001010001000101000101000101000010000000101000101000101000100010100010100010100001 Output: 1001000100001001001001001000100100100100100100010100100010000100100100100100...

I got 20 times Presentation Error before AC. :( :( In output specification "The second line is a series of slot sizes (in descending order) separated by spaces" Input: 1 10 1000000 My Output: 1 1 1 # 10 5@2 8@2 # 1000000 29@25@23@11@9 832040@121393@46368@144@55 # Note: Here # represent the blank lin...

I explain the sample input output, then the problem is very clear for understand. Original string: ufrn a replace by: t b replace by: o c replace by: w d replace by: k e replace by: q f replace by: z g replace by: f h replace by: n i replace by: y j replace by: i k replace by: c l replace by: m m re...

Try this Input: 10 5 1 2 3 5 8 A 5 8 5 3 2 1 A 5 8 5 3 2 1 abcd 5 8 5 3 2 1 ABCDEFG 5 5 4 3 2 1 ABCDE 5 5 4 3 2 1 A a B b C c D d E e 1 13 ABCD 1 1836311903 aaaaaaaaaabbbbbbbbbbcccccccccccDdddddddddddddddddddd 1 4 ABC 1 2 a Output: A#### ####A ##### EDCBA DCBA DCBA #####A ###########################...

Remove Code After AC

I go WA For this test Case
Input: Output:

Input: 153 1 1 2 1 2 2 3 1 3 2 3 3 4 1 4 2 4 3 4 4 5 1 5 2 5 3 5 4 5 5 6 1 6 2 6 3 6 4 6 5 6 6 7 1 7 2 7 3 7 4 7 5 7 6 7 7 8 1 8 2 8 3 8 4 8 5 8 6 8 7 8 8 9 1 9 2 9 3 9 4 9 5 9 6 9 7 9 8 9 9 10 1 10 2 10 3 10 4 10 5 10 6 10 7 10 8 10 9 10 10 11 1 11 2 11 3 11 4 11 5 11 6 11 7 11 8 11 9 11 10 11 11 1...

Read this line carefully " When the machine is switched on in the morning, with an empty output store, it immediately moves 1 coin into the output store. When that has been dispensed it will then move 2 coins, then 3, and so on until it reaches some preset limit k. It then recycles back to 1, then 2...

For grams to Calories, you are given a rules that:

1g fat = 9 Calories,
1g protein = 4 Calories,
1g sugar = 4 Calories,
1g starch = 4 Calories,
1g alcohol = 7 Calories

I think now the problem is very easy.

Remember that use double for all calculation

BFS problem Maximum length of M=100 For each location(x,y) you got four adjacency location 1.(x-1,y) 2.(x+1,y) 3.(x,y-1) 4.(x,y+1) When taking in the input, keep a list of all 1-nodes and all 3-nodes. For each 1-node, find the distance to the closest 3-node. distance=abs(1.x - 3.x) + abs(1.y - 3.y)....

BFS Problem Pouring rule: Pouring from one jug to the other stops when the first jug is empty or the second jug is full, whichever comes first. For example, if A has 5 gallons and B has 6 gallons and a capacity of 8, then pouring from A to B leaves B full and 3 gallons in A. 1. At first push to queu...

BFS Problem I represent the 4 digit as integer i.e. if 4 digits are 0 2 0 1 then I represent is 201, or 1 2 3 1 represent 1231 At first pregenerate all adjacency for 0 to 9999 For each value you got 8 adjacency value Example If the 4 digit are 0 1 0 0 so, the value is 100 ---set n=value ---set m=n%1...

BFS problem This is just a BFS problem with a bit of math. 1. Find all adjacency using this condition, consider two holes connected if the distance between them is less than or equal to v*m*60. 2. Run BFS on the gopher holes to destination hole. 3. If gopher reach to destination hole then print leng...