### Re: 10137 - The Trip, get WA

Posted:

**Tue Feb 18, 2014 9:52 pm**Try solving it without using floating point.

Page **10** of **11**

Posted: **Tue Feb 18, 2014 9:52 pm**

Try solving it without using floating point.

Posted: **Wed Feb 19, 2014 3:51 pm**

I used int

Posted: **Wed Feb 19, 2014 9:28 pm**

This line uses floating point:

printf("$%.2f\n", ((give > take) ? give : take) / 100.0f);

printf("$%.2f\n", ((give > take) ? give : take) / 100.0f);

Posted: **Thu Feb 20, 2014 11:00 am**

Thank you. This is the point.

Posted: **Tue Mar 11, 2014 8:15 am**

Hi...I don't know why i m getting error...i have tried several inputs and those work...any hints experts?

Code: Select all

```
#include<iostream>
#include<math.h>
#include<stdio.h>
using namespace std;
int main()
{
long input;
double buck;
double average = 0.00;
double positivesum = 0.00;
double negativesum = 0.00;
double track;
double* arr;
while(cin >> input && input != 0)
{
arr = new double[input];
for(int i = 0; i < input; i++)
{
cin >> buck;
if(buck >= 0.00)
{
average = average + buck;
arr[i] = buck;
}
}
average = average/double(input);
//double rounded_down = floorf(average * 100) / 100; /* Result: 37.77 */
double nearest = floorf(average * 100 + 0.5) / 100; /* Result: 37.78 */
//double rounded_up = ceilf(average * 100) / 100; /* Result: 37.78 */
for(int i = 0; i < input; i++)
{
if(arr[i] > average)
{
positivesum += (arr[i]-nearest);
}
else
{
negativesum += (nearest-arr[i]);
}
}
if(positivesum < negativesum)
{
printf("$");
printf("%0.2lf\n",positivesum);
}
else
{
printf("$");
printf("%0.2lf\n",negativesum);
}
positivesum = 0.00;
negativesum = 0.00;
average = 0.00;
}
return 0;
}
```

Posted: **Tue Mar 11, 2014 8:03 pm**

brianfry713 wrote:brianfry713 wrote:brianfry713 wrote:Try solving it without using floating point.

Posted: **Tue Mar 11, 2014 8:26 pm**

I have modified the program without using floating point. But same problem.

Posted: **Wed Mar 12, 2014 8:26 pm**

Post your updated code.

Posted: **Thu Mar 13, 2014 4:11 am**

Hi...Here is my updated code.brianfry713 wrote:Post your updated code.

Code: Select all

```
#include<iostream>
#include<math.h>
#include<stdio.h>
using namespace std;
int main()
{
long input;
double buck;
double average = 0;
double positivesum = 0;
double negativesum = 0;
double track;
double* arr;
while(cin >> input && input != 0)
{
arr = new double[input];
for(int i = 0; i < input; i++)
{
cin >> buck;
if(buck >= 0)
{
average = average + buck;
arr[i] = buck;
}
}
average = average/input;
double nearest = floorf(average * 100.0 + 0.5) / 100.0;
for(int i = 0; i < input; i++)
{
if(arr[i] > average)
{
positivesum += (arr[i]-nearest);
}
else
{
negativesum += (nearest-arr[i]);
}
}
if(positivesum < negativesum)
{
printf("$%0.2lf\n",positivesum);
}
else
{
printf("$%0.2lf\n",negativesum);
}
positivesum = 0;
negativesum = 0;
average = 0;
}
return 0;
}
```

Posted: **Thu Mar 13, 2014 8:24 pm**

Try solving it without using floating point.

Posted: **Sun Mar 23, 2014 6:02 am**

Hi...I have changed my code little bit..but still WA....can you please give me some test input?I am sure i am getting WA for formatting..

#include<iostream>

#include<math.h>

#include<stdio.h>

using namespace std;

int main()

{

long input;

double buck;

double average = 0;

double positivesum = 0;

double negativesum = 0;

double* arr;

while(cin >> input && input != 0)

{

arr = new double[input];

for(int i = 0; i < input; i++)

{

cin >> buck;

if(buck >= 0)

{

average = average + buck;

arr* = buck;*

}

}

average = average/input;

double nearest = floorf(average * 100 + 0.5) / 100;

for(int i = 0; i < input; i++)

{

if(arr* > average)*

{

positivesum += (arr*-nearest); *

}

else

{

negativesum += (nearest-arr*); *

}

}

if(positivesum < negativesum)

{

printf("$");

printf("%0.2lf\n",positivesum);

}

else

{

printf("$");

printf("%0.2lf\n",negativesum);

}

positivesum = 0;

negativesum = 0;

average = 0;

}

return 0;

}

#include<iostream>

#include<math.h>

#include<stdio.h>

using namespace std;

int main()

{

long input;

double buck;

double average = 0;

double positivesum = 0;

double negativesum = 0;

double* arr;

while(cin >> input && input != 0)

{

arr = new double[input];

for(int i = 0; i < input; i++)

{

cin >> buck;

if(buck >= 0)

{

average = average + buck;

arr

}

}

average = average/input;

double nearest = floorf(average * 100 + 0.5) / 100;

for(int i = 0; i < input; i++)

{

if(arr

{

positivesum += (arr

}

else

{

negativesum += (nearest-arr

}

}

if(positivesum < negativesum)

{

printf("$");

printf("%0.2lf\n",positivesum);

}

else

{

printf("$");

printf("%0.2lf\n",negativesum);

}

positivesum = 0;

negativesum = 0;

average = 0;

}

return 0;

}

Posted: **Tue Mar 25, 2014 12:12 am**

Don't use double, only use integers.brianfry713 wrote:Try solving it without using floating point.

Posted: **Mon Aug 11, 2014 6:28 pm**

I just got AC for this problem and wanted to share a small tip.

I solved the problem using whole numbers because I am not confident about floating points for this problem. To take input, I used the following code:

Then, for each person who spent more than averageExpense, they should be re-imbursed.

Each unit is

"averageExpense" is the MINIMUM amount that should be spent by each person.

Each unit from "residue" is then given to the first persons who spent more than the average.

Example:

Expenses = $1.02

Expenses in cents = 102 cents

No. of people = 5

AverageExpense = 20 cents

Residue = 2

People 1 should spend 20 + 1

People 2 should spend 20 + 1

People 3 should spend 20

People 4 should spend 20

People 5 should spend 20

I solved the problem using whole numbers because I am not confident about floating points for this problem. To take input, I used the following code:

Code: Select all

```
for (int i = 0; i < n; i++)
{
scanf("%ld.%ld", &dollarPart, ¢sPart);
expensesInCents[i] = (dollarPart * 100) + centsPart;
totalExpenses += expensesInCents[i];
}
averageExpense = (totalExpenses / n);
residue = (totalExpenses % n);
```

Each unit is

"averageExpense" is the MINIMUM amount that should be spent by each person.

Each unit from "residue" is then given to the first persons who spent more than the average.

Example:

Expenses = $1.02

Expenses in cents = 102 cents

No. of people = 5

AverageExpense = 20 cents

Residue = 2

People 1 should spend 20 + 1

People 2 should spend 20 + 1

People 3 should spend 20

People 4 should spend 20

People 5 should spend 20

Posted: **Sat Sep 06, 2014 6:28 pm**

for (int i = 0; i < numPpl; i++) {

cin >> temp;

avg += (int) (temp * 10000 + 1e-9) / numPpl;

cents= (int) (temp * 100 + 1e-9);

top = max(top, cents);

Can someone explain " + 1e-9 " ???

thx a lot........

take it as a habit and if you want to compare to reals

use

abs(x-y) <= 1e-9

Posted: **Sat Sep 06, 2014 8:28 pm**

hey guys !

again help please ::

my code as follows
it passed all the tests in this forums

the problem is with the test
the output is clearly 0.01 as my approach

but AC output is 0.00 -_- did i miss sth

or there is a problem with the judge

again help please ::

my code as follows

Code: Select all

```
#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
long long n;
while(cin >> n && n != 0)
{
long long *exp = new long long[n];
long long avg = 0, res;
for(long long i = 0; i<n; i++)
{
double x;
cin>>x;
x += 1e-9;
exp[i] = 100*x;
avg += exp[i];
}
res = avg%n;
avg /= n;
long long count1 = 0, count2 = 0;
long long pos = 0, neg = 0;
for(long long i = 0; i <n; i++)
{
long long cash = exp[i] - avg;
if(cash > 0)
{
pos += cash;
count1++;
}
else
{
neg -= cash;
count2++;
}
}
long long res1 = res;
for(long long i = 1; i<=count1 && res>0; i++ , res--)
{
pos--;
}
for(long long i = 1; i<=count2 && res1>0; i++ , res1--)
{
neg++;
}
printf("$%.2f\n" , ((pos < neg)? pos : neg) / 100.0f);
}
return 0;
}
```

the problem is with the test

Code: Select all

```
15
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.01
0.03
```

but AC output is 0.00 -_- did i miss sth

or there is a problem with the judge