## 10093 - An Easy Problem!

**Moderator:** Board moderators

### 10093 A hard problem!

I don't know what I am doing wrong with this problem.

I considered that there could be + or - sign before a number.

If input is 0 output is 2 , isn't it.

I also stared to loop from (max+1) where max is the numerical maximum character ( ie A = 10 and a = 26 and so on).

Then later I converted it to decimal , considering all the bases, and checked whether it is divisible by (Base - 1).

What am I doing wrong.

I will not post my code as yet ...

Can anyone give me some critical input.

Thanx

I considered that there could be + or - sign before a number.

If input is 0 output is 2 , isn't it.

I also stared to loop from (max+1) where max is the numerical maximum character ( ie A = 10 and a = 26 and so on).

Then later I converted it to decimal , considering all the bases, and checked whether it is divisible by (Base - 1).

What am I doing wrong.

I will not post my code as yet ...

Can anyone give me some critical input.

Thanx

### What I consider

Hi Sohel,

Below is what I consider in this program. For your reference.

a. Don't take care of +/-. Even there are + or - symbol, the result should be the same.

b.Take care of white space, tab. In fact. this kind of characters are ALL

skipped.

c.Check invalid character for certain base. For example, 222 is an invalid

base 2 number. AAA is invalid base 2~10 number.

d.Note the real value, for example,

111 base 2 = 7, but 111 base 4 = 21.

Below is what I consider in this program. For your reference.

a. Don't take care of +/-. Even there are + or - symbol, the result should be the same.

b.Take care of white space, tab. In fact. this kind of characters are ALL

skipped.

c.Check invalid character for certain base. For example, 222 is an invalid

base 2 number. AAA is invalid base 2~10 number.

d.Note the real value, for example,

111 base 2 = 7, but 111 base 4 = 21.

### still don't get it

I considered the things you have mentioned but still get WA.

This time I will post my code:

[cpp]

deleted after getting AC.

[/cpp]

Can somebody give a quick scan on this trivial code and point out the mistake.

Thanks.

This time I will post my code:

[cpp]

deleted after getting AC.

[/cpp]

Can somebody give a quick scan on this trivial code and point out the mistake.

Thanks.

Last edited by sohel on Mon Mar 15, 2004 8:52 am, edited 2 times in total.

### confusion

I am wondering whehter

long long is enough to solve this problem.

If I convert the given number to base 10 ( for each base ) won't it fit

into long long or

do i have to use any other technique to find validity.

If the latter is true , can someone give me some hints on that.

Thanks.

long long is enough to solve this problem.

If I convert the given number to base 10 ( for each base ) won't it fit

into long long or

do i have to use any other technique to find validity.

If the latter is true , can someone give me some hints on that.

Thanks.

- little joey
- Guru
**Posts:**1080**Joined:**Thu Dec 19, 2002 7:37 pm

### isdiv

I realized that long long is not big enough..... and so I resorted to string division... but still WA!

[cpp]

bool isdiv(char str[], int b)

{

int i,k,l;

l = strlen(str);

int sum = 0;

for(i=0;i<l;i++)

{

if( isdigit( str

I use to following function to check whether a number in base b is divisible by (b-1).One hint: how do you determine if a decimal number of arbitrary length is divisible by 9?

[cpp]

bool isdiv(char str[], int b)

{

int i,k,l;

l = strlen(str);

int sum = 0;

for(i=0;i<l;i++)

{

if( isdigit( str

*) )*

k = strk = str

*- '0';*

else if( strelse if( str

*<='Z')*

k = strk = str

*- 'A' + 10;*

else

k = strelse

k = str

*- 'a' + 36;*

sum = sum*b + k;

sum = sum % (b-1);

}

if(sum)

return true;

return false;

}

[/cpp]

Is there anything wrong with this?

Can you give some critcal inputs where this function fails.

Thanks.

sum = sum*b + k;

sum = sum % (b-1);

}

if(sum)

return true;

return false;

}

[/cpp]

Is there anything wrong with this?

Can you give some critcal inputs where this function fails.

Thanks.

- little joey
- Guru
**Posts:**1080**Joined:**Thu Dec 19, 2002 7:37 pm

### dev-c++ OK but OJ compile error

I've been solving the problem 10093 on my computer and it compiles perfectly ok (dev-c++), but when i send it to OJ i get compile error. Is something wrong with my code or what?

// code deleted after AC

// code deleted after AC

Last edited by tRipper on Sun Apr 10, 2005 9:45 am, edited 1 time in total.

- Krzysztof Duleba
- Guru
**Posts:**584**Joined:**Thu Jun 19, 2003 3:48 am**Location:**Sanok, Poland-
**Contact:**

### An Easy Problem!

I got WA, but I couldn't find bugs of my code.

Could anyone check my code?

Or, if you have Accepted code, compare the output of your code with the my code one?

Here is my code.
Thank you.

Could anyone check my code?

Or, if you have Accepted code, compare the output of your code with the my code one?

Here is my code.

Code: Select all

```
cut after Accepted, thanks
```

Last edited by tan_Yui on Tue Jun 14, 2005 7:30 am, edited 1 time in total.

### Re: An Easy Problem!

I'm waiting for somebody's help still now.

It's not easy problem for me ....

Thank you.

It's not easy problem for me ....

Thank you.

### 10093: Why WA?

I've still got WA,can anyone help me?

#include <iostream.h>

int f(char a)

{

if(a>='0' && a<='9')

return a-'0';

if(a>='a' && a<='z')

return a-'a'+36;

if(a>='A' && a<='Z')

return a-'A'+10;

}

int main()

{

char line[250];

int max,tmp,i,j;

unsigned long r;

line[0]='\0';

while(cin.getline(line,250) && line[0])

{

max=-1;

for(i=0;line

#include <iostream.h>

int f(char a)

{

if(a>='0' && a<='9')

return a-'0';

if(a>='a' && a<='z')

return a-'a'+36;

if(a>='A' && a<='Z')

return a-'A'+10;

}

int main()

{

char line[250];

int max,tmp,i,j;

unsigned long r;

line[0]='\0';

while(cin.getline(line,250) && line[0])

{

max=-1;

for(i=0;line

*;i++)*

{

tmp=f(line{

tmp=f(line

*);*

if(max<tmp)

max=tmp;

}

max= max<2 ? 2:max+1;

for(i=max;i<=62;i++)

{

r=0;

for(j=0;line[j];j++)

r=(r*i+f(line[j]))%(i-1);

if(r==0)

break;

}

if(i==63)

cout<<"such number is impossible!"<<endl;

else cout<<i<<endl;

line[0]='\0';

}

return 0;

}if(max<tmp)

max=tmp;

}

max= max<2 ? 2:max+1;

for(i=max;i<=62;i++)

{

r=0;

for(j=0;line[j];j++)

r=(r*i+f(line[j]))%(i-1);

if(r==0)

break;

}

if(i==63)

cout<<"such number is impossible!"<<endl;

else cout<<i<<endl;

line[0]='\0';

}

return 0;

}