## 895 - Word Problem

All about problems in Volume 8. If there is a thread about your problem, please use it. If not, create one with its number in the subject.

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rudy yulianto
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Posts: 4
Joined: Sun Sep 09, 2007 1:42 pm
Location: Indonesia
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### run time error

i have been try some input from Jan
abc
bcd
cde
def
eee
eff
eggg
ffff
#
e e e
#
and my output
• 1
but my submission is run time error

it's my code in C

Code: Select all

``````#include<stdio.h>
#include<string.h>

int counter[1232];
int main()
{
int flag;
char dic[1233][13];
char puzzle[1234][13];
int i =-1,j=-1;

int a,b,len,c;
char buff[13];
int k;
do
{
i++;
gets(dic[i]);
}while(dic[i][0]!='#');
j=-1;
do
{
j++;
gets(puzzle[j]);
}while(puzzle[j][0]!= '#');

for(a=0;a<j;a++)
{
for(b=0;b<i;b++)
{
strcpy(buff,puzzle[a]);
for(c=0;c<strlen(dic[b]);c++)
{
flag=1;
for(k=0;k<strlen(buff);k++)
{
if(dic[b][c] != buff[k])
flag=0;

else
{
flag=1;
buff[k]=' ';
break;
}
}
if(flag==0)break;
}
if(flag==1) counter[a]++;

}
printf("%d\n",counter[a]);
}

return 0;
}
``````
please help me, give some reason why RTE and give me some IO..thx before...
sorry my english is bad

Jan
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Posts: 1334
Joined: Wed Jun 22, 2005 10:58 pm
Location: Dhaka, Bangladesh
Contact:
How did you know that there are less than 1234 word puzzles? The problem states that the dictionary can have at most 1000 words. But there is no restriction for the number of word puzzles. So, just pick a puzzle, solve it and print the result until you get the '#'.
Ami ekhono shopno dekhi...
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Jehad Uddin
Learning poster
Posts: 74
Joined: Fri May 08, 2009 5:16 pm

### Re: 895 - Word Problem

Hello every body,i am getting frustrated with the problem.Though i passed all the I/Os from the board.Here is my code.Pls help me.

Code: Select all

``````#include<iostream>
#include<string>
using namespace std;
int main()
{
char dic[1002][20];
long int a[1002][27];
long int word[27];
long int i,j,k,l,m;
char str[20];
while(cin>>dic[0])
{
for(i=0;i<26;i++) a[0][i]=0;
for(i=0;i<strlen(dic[0]);i++)
a[0][dic[0][i]-97]++;
k=1;
while(1)
{
cin>>dic[k];
if(strcmp(dic[k],"#")==0) break;
for(i=0;i<26;i++) a[k][i]=0;
for(i=0;i<strlen(dic[k]);i++)
a[k][dic[k][i]-97]++;
k++;

}
getchar();
while(1)
{
gets(str);
if(str[0]=='#') break;
for(i=0;i<26;i++)
word[i]=0;
for(i=0;i<strlen(str);i++)
if(str[i]>=97&&str[i]<=122)  word[str[i]-97]++;
m=0;l=1;
for(i=0;i<k;i++)
{
for(j=0,l=1;j<26;j++)
if(word[j]<a[i][j])
{
l=0;
break;
}

if(l) m++;
}

cout<<m<<endl;

}

}

return 0;
}``````
Advanced thanks for the helpers.

Shafaet_du
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Posts: 147
Joined: Mon Jun 07, 2010 11:43 am
Location: University Of Dhaka,Bangladesh
Contact:

### Re: 895 - Word Problem

sample

Code: Select all

``````hello
this
hiso
csedu
dhaka
niceprob
rivers
cricket
acm
acm
this
string
c
you
#
a c c c h i m
s r w d d g d
h s a i o c m
c a q r t r r
h l l y o o u
#``````
output:

Code: Select all

``````3
0
4
1
1``````

receme
New poster
Posts: 17
Joined: Thu Jul 01, 2010 11:55 am

### Re: 895 - Word Problem

Solved a moment ago ...I used LCS. It takes 0.020 sec.

20717TZ
New poster
Posts: 33
Joined: Tue Apr 27, 2004 7:41 pm
Location: Santa Clara / Mountain View, CA, USA
Contact:

### Re:

sohel wrote:
Do you consider the case that same word may appear more than once
in the dictionary ?
You mean the dictionary can contain the same word twice.

For example :

cat
cat
dog
lion
#
c a t
#

will output 2.

I applied the method that .. mentioned and got AC.. but still can't figure out why the original was rejected.
WOW, I used a "std::map<string, map<char, int> >" to intentionally handle the case that same word appears twice in the dictionary, and I don't think it should output 2, because in the problem description, it states very clearly:
For each puzzle line in the input, a single line of output should be produced, containing the number of different words in the dictionary that can be formed using the letters in the puzzle line.
And I got a "Wrong Answer" verdict.

My code runs with the following input:

Code: Select all

``````ant
bee
cat
dog
ewe
fly
gnu
abcdefgh
abcdefghij
x
x
xxx
y
z
#
b e w
b b e e w w
t a n c u g d
x
x y
x y z
x x x
#``````
giving the output:

Code: Select all

``````0
2
3
1
2
3
2``````
I Believe I Can - leestime.com

20717TZ
New poster
Posts: 33
Joined: Tue Apr 27, 2004 7:41 pm
Location: Santa Clara / Mountain View, CA, USA
Contact:

### Re: 895 - Word Problem

Shafaet_du wrote:sample

Code: Select all

``````hello
this
hiso
csedu
dhaka
niceprob
rivers
cricket
acm
acm
this
string
c
you
#
a c c c h i m
s r w d d g d
h s a i o c m
c a q r t r r
h l l y o o u
#``````
output:

Code: Select all

``````3
0
4
1
1``````
I think it should be:

Code: Select all

``````2
0
3
1
1``````
Because in the problem description, it states very clearly:
For each puzzle line in the input, a single line of output should be produced, containing the number of DIFFERENT words in the dictionary that can be formed using the letters in the puzzle line.
But I got a "Wrong Answer" verdict.
I Believe I Can - leestime.com

brianfry713
Guru
Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 895 - Word Problem

There are repeated words in the judge's input, and they should be counted multiple times in the output.
Check input and AC output for thousands of problems on uDebug!

uDebug
A great helper
Posts: 475
Joined: Tue Jul 24, 2012 4:23 pm

### Re: 895 - Word Problem

Replying to follow the thread.
Check input and AC output for over 7,500 problems on uDebug!

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